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DaGr8Gatzby's avatar
16 years ago
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DaGr8Gatzby
Drunk by Myself
this post has been archived.
lucas's avatar
16 years ago
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lucas
i ❤ demo
dude i'm typing up one of my assignments right now

saturday night homework is the real deal
DaGr8Gatzby's avatar
16 years ago
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DaGr8Gatzby
Drunk by Myself
Sorry. I'm dumb.

Studying chemistry and we're on avogadro's number. And I'm a fuckin idiot because I just figured this shit out. Basic Algebraic manipulation:

You basically have to derive a mass per gram that is defined by Avogadro's #:

6.022*10^23 (This is the number of carbon atoms in exactly 12g of a pure isotope of Carbon with mass 12 amu)

Carbon's atomic number is 6
Atomic mass = 12.01

From this, the secondary number is derived:


  6.022 * 10^23 C atoms       12 amu
________________________* ______________ =    12 G 
             
          1                   1 C atom


This will cancel out to:

6.022 * 10^23 C amu = 1 G

And from this we derive:

               1 gram
1 amu =   _________________   =  1.661 * 10^-24
   
           6.022 * 10^23 C 


1. Calculate amu
2. Multiply by the derived unit from Avogadro's number

Ex. - Find the mass of an atom of Fe (Note this is a random element I chose)

1. Calculate amu

Element: Fe
Atomic #: 26
Atomic Mass: 55.85

Amu = 55.85 amu

2. Multiply by derived value

55.85 amu       1.661 * 10^-24 g
___________ *   ______________    =  9.277 g/atom

   1                   1   



.... I'm a loser ... fuckin saturday night ... whatever.

Edit - Second Try
DaGr8Gatzby's avatar
16 years ago
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DaGr8Gatzby
Drunk by Myself
Lucas - Used Terminal.app to get an actual monospaced font ... Like the final result?
lucas's avatar
16 years ago
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lucas
i ❤ demo
yeah, it looks pretty good :)
lucas's avatar
16 years ago
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lucas
i ❤ demo
and you archived/reposted your post, so now my post is first :P
dannyp's avatar
16 years ago
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dannyp
dʎuuɐp
damn good job on the blockquote math diagrams!